设z=z(x,y)是由方程2sin(x+2y-3z)=x+2y-3z所确定的隐函数,并设cos(x+2y-3z)≠½,求偏导数y

问题描述:

设z=z(x,y)是由方程2sin(x+2y-3z)=x+2y-3z所确定的隐函数,并设cos(x+2y-3z)≠½,求偏导数y

2cos(x+2y-3z)*(2-3dz/dy)=2-3dz/dy
因为cos(x+2y-3z)≠½
所以2-3dz/dy=0
dz/dy=2/3