(1) 1+x\1-x÷(x-2x\1-x)(2) (1+1\x-1)÷(x²\x²-1) - (x+1\X)注:分子\分母最好是初二正在学习的解题方法!

问题描述:

(1) 1+x\1-x÷(x-2x\1-x)
(2) (1+1\x-1)÷(x²\x²-1) - (x+1\X)
注:分子\分母
最好是初二正在学习的解题方法!

(1)原式=1+x\1-x×(1-x\x-2x)
=1+(1-2)
=0
(2)原式=(1+1\X-1)÷{X²\(X+1)(X-1)}-(X+1\X)
=(X-1\X-1+1\X-1)×{(X+1)(X-1)\X²}-(X+1\X)
=(X+1\X)-(X+1\X)
=0