ax^2+3ax-1因式分解
问题描述：
ax^2+3ax-1因式分解
答
解ax²+3ax-1=0得
x1=(-3a+根号(9a²+4a))/2ax2=(-3a-根号(9a²+4a))/2a
∴ax²+3ax-1
=a(x-x1)(x-x2)